Calculate expressions involving greatest integer functions Precalculus

Let f be the function defined as \lfloor x-\dfrac{3}{5} \rfloor. What is f\left( \dfrac{3}{7} \right) ?

f\left( \dfrac{3}{7} \right)=0

f\left( \dfrac{3}{7} \right)=1

f\left( \dfrac{3}{7} \right)=-1

f\left( \dfrac{3}{7} \right)=-2

Let f be the function defined as \lfloor x+\dfrac{1}{2} \rfloor. What is f\left( \dfrac{3}{4} \right) ?

f\left( \dfrac{3}{4} \right)=0

f\left( \dfrac{3}{4} \right)=1

f\left( \dfrac{3}{4} \right)=2

f\left( \dfrac{3}{4} \right)=3

Let f be the function defined as \lfloor 3x-\dfrac{1}{4} \rfloor. What is f\left( -\dfrac{1}{2} \right) ?

f\left( -\dfrac{1}{2} \right)=-4

f\left( -\dfrac{1}{2} \right)=-3

f\left( -\dfrac{1}{2} \right)=-2

f\left( -\dfrac{1}{2} \right)=-1

Let f be the function defined as \lfloor 5x+\dfrac{2}{3} \rfloor. What is f\left( -\dfrac{1}{3} \right) ?

f\left( -\dfrac{1}{3} \right)=-5

f\left( -\dfrac{1}{3} \right)=-3

f\left( -\dfrac{1}{3} \right)=-1

f\left( -\dfrac{1}{3} \right)=0

Let f be the function defined as \lfloor x-\dfrac{7}{5} \rfloor. What is f\left( \dfrac{3}{10} \right) ?

f\left( \dfrac{3}{10} \right)=-2

f\left( \dfrac{3}{10} \right)=-1

f\left( \dfrac{3}{10} \right)=0

f\left( \dfrac{3}{10} \right)=1

Let f be the function defined as \lfloor x-\dfrac{2}{3} \rfloor . What is f\left( \dfrac{5}{6} \right) ?

f\left( \dfrac{5}{6} \right)=-1

f\left( \dfrac{5}{6} \right)=0

f\left( \dfrac{5}{6} \right)=1

f\left( \dfrac{5}{6} \right)=2

Let f be the function defined as \lfloor-3x+\dfrac{1}{4} \rfloor . What is f\left( \dfrac{3}{8} \right) ?

f\left( \dfrac{3}{8} \right)=-1

f\left( \dfrac{3}{8} \right)=0

f\left( \dfrac{3}{8} \right)=1

f\left( \dfrac{3}{8} \right)=2