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  1. Home
  2. 12th grade
  3. Precalculus
  4. Exercise : Determine the domain and range of a function defined by a graph

Determine the domain and range of a function defined by a graph Precalculus

Determine the domain and range of the following functions.

-

The domain is the set of the possible x -values. The graph spreads horizontally from -2 to 3. Therefore the domain is \left[-2{,}3\right].

The range is the set of possible y -values. Here, the graph spreads vertically from -1 to 3. Therefore the range is \left[-1{,}3\right].

  • The domain is : \left[-2 , 3\right]
  • The range is : \left[-1 , 3\right]
-

The domain is the set of the possible x -values. The graph spreads horizontally from -1 to 1. Therefore the domain is \left[-1{,}1\right].

The range is the set of possible y -values. Here, the graph spreads vertically from -4 to 2. Therefore the range is \left[-4{,}2\right].

  • The domain is : \left[-1{,}1\right]
  • The range is : \left[-4{,}2\right]
-

The domain is the set of the possible x -values. The graph spreads horizontally from -2 to 4 Therefore the domain is \left[-2{,}4\right].

The range is the set of possible y -values. Here, the graph spreads vertically from 0 to 4. So the range of f is \left[0{,}4\right].

  • The domain is : \left[-2 , 4\right]
  • The range is : \left[0 , 4\right]
-

The domain is the set of the possible x -values. The graph spreads horizontally from -3 to 2 but it is not defined from -1 to 1. Therefore the domain is \left[-3,-1\right] \cup \left[1{,}2\right].

The range is the set of possible y -values. Here, the graph spreads vertically from 0 to 4. Therefore the range is \left[0{,}4\right].

  • The domain is : \left[-3 , -1\right] \cup \left[1{,}2\right]
  • The range is : \left[0 , 4\right]
-

The domain is the set of the possible x -values. The graph spreads horizontally from -2 to 2. Therefore the domain is \left[-2{,}2\right].

The range is the set of possible y -values. Here, the graph spreads vertically from -2 to 2. Since f\left(0\right)=1, 2 does not lie in the range of f. Therefore the range is \left[-2{,}2\right).

  • The domain is : \left[-2 ,2\right]
  • The range is : \left[-2{,}2\right)
-

The domain is the set of the possible x -values. The graph spreads horizontally from -2 to 4 but is not defined at x_0 = 4. Therefore the domain is \left[-2{,}4\right).

The range is the set of possible y -values. Here, the second coordinates can only take the integers between -2 and 3. Therefore, the range of f is \{-2,-1{,}0{,}1{,}2{,}3\}.

  • The domain is : \left[-2 , 4\right)
  • The range is : \{-2,-1{,}0{,}1{,}2{,}3\}
-

The domain is the set of the possible x -values. The graph spreads horizontally from -3 to 2. Therefore the domain is \left[-1{,}2\right].

The range is the set of possible y -values. Here, the graph spreads vertically from 0 to 3, there is a hole in point 3 and f\left(0\right)=4. Therefore the range is \left[0{,}3\right) \cup \{4\}.

  • The domain is : \left[-3 , 2\right]
  • The range is : \left[0, 3\right) \cup \{4\}

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See also
  • Course : Relations and functions
  • Exercise : Determine cartesian coordinates of points of the plan
  • Exercise : Add and subtract functions defined by equations
  • Exercise : Calculate the average rate of change of a function between two points using the equation of the function
  • Exercise : Find the x- and y- intercept of a function defined by a graph
  • Exercise : Compose two functions
  • Exercise : Find the inverse of a function
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