Solve equations with radical functions Precalculus

Solve the following equations.

\left(2x+3\right)^{-1/2} = 2

x=-\dfrac{11}{8}

x=-\dfrac{1}{2}

x=\dfrac{1}{2}

x=\dfrac{13}{8}

\left(4x-3\right)^{-1/4} = 5

x=2

x=157

x=\dfrac{469}{625}

x=\dfrac{23}{4}

\left(5x+8\right)^{-2/3} = 4

x=0

x=\dfrac{8}{5}

x=-\dfrac{63}{40}

x=-\dfrac{4}{5}

\left(3x-5\right)^{1/2} = 7

x=4

x=18

x=\dfrac{44}{3}

x=\dfrac{2}{3}

\sqrt{2x^{2}+5x-3}=x-3

x=-12

x=-12 and x=1

x=1

The equation has no solution.

\sqrt{x^{2}+11x-3}=x-4

x=-4

x=4

The equation has no solution.

x=1

\sqrt{13x+43}=x+5

x=-3 and x=6

x=6

The equation has no solution.

x=3 and x=-6