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  1. Home
  2. 12th grade
  3. Algebra I
  4. Exercise : Solve a linear equation using graphs

Solve a linear equation using graphs Algebra I

Solve the following linear equations using the given graph.

3x - 2 = 4

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On the same graph, we draw the lines whose equations are:

\begin{cases} y=3x-2 \cr \cr y=4 \end{cases}

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We can see on the graph that the lines intersect at \left(2{,}4\right).

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The solution is x = 2.

8x - 3= 1

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On the same graph, we draw the lines whose equations are:

\begin{cases} y=8x-3 \cr \cr y=1 \end{cases}

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We can see on the graph that the lines intersect at \left(\dfrac{1}{2},1\right).

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The solution is x = \dfrac{1}{2}.

-2x +3= x

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On the same graph, we draw the lines whose equations are:

\begin{cases} y=-2x+3 \cr \cr y=x \end{cases}

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We can see on the graph that the lines intersect at \left(1{,}1\right).

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The solution is x =1.

-3x +5 = -1

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On the same graph, we draw the lines whose equations are:

\begin{cases} y=-3x+5 \cr \cr y=-1 \end{cases}

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We can see on the graph that the lines intersect at \left(2,-1\right).

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The solution is x = 2.

-3x - 4 = -x

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On the same graph, we draw the lines whose equations are:

\begin{cases} y=-3x-4 \cr \cr y=-x \end{cases}

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We can see on the graph that the lines intersect at \left(-2{,}2\right).

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The solution is x = -2.

1-4x = -3

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On the same graph, we draw the lines whose equations are:

\begin{cases} y=1-4x \cr \cr y=-3 \end{cases}

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We can see on the graph that the lines intersect at \left(1,-3\right).

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The solution is x = 1.

7x - 2 = \dfrac{3}{2}

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On the same graph, we draw the lines whose equations are:

\begin{cases} y=7x-2 \cr \cr y=-\dfrac{3}{2} \end{cases}

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We can see on the graph that the lines intersect at \left(\dfrac{1}{2},\dfrac{3}{2}\right).

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The solution is x = \dfrac{1}{2}.

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See also
  • Course : Linear equations
  • Exercise : Solve a linear equation with algebra tiles
  • Exercise : Solve a linear equation using simple operations
  • Exercise : Solve a linear equation with variables on both sides
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