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  1. Home
  2. 12th grade
  3. Algebra I
  4. Exercise : Solve a linear equation using simple operations

Solve a linear equation using simple operations Algebra I

Solve the following linear equations using simple operations.

-2x - 3 = 11

Consider the equation:

-2x-3=11

Add 3 to both sides:

-2x=14

Divide both sides by -2:

x=\dfrac{14}{-2}

x=-7

The solution is x = -7.

3x + 2 = 17

Consider the equation:

3x+2=17

Subtract 2 from both sides:

3x=15

Divide both sides by 3:

x = \dfrac {15} {3}

x = 5

The solution is x=5.

-4x+1=-3

Consider the equation:

-4x+1=-3

Subtract 1 from both sides:

-4x = -4

Divide both sides by -4:

x = \dfrac {-4} {- 4}

x = 1

The solution is x=1.

5x-2 = 18

Consider the equation:

5x-2=18

Add 2 to both sides:

5x=20

Divide both sides by 5:

x = \dfrac {20} {5}

x =4

The solution is x=4.

-2x-10 = 4

Consider the equation:

-2x-10 = 4

Add 10 to both sides:

-2x=14

Divide both sides by -2:

x=\dfrac{14}{-2}

x=-7

The solution is x=-7

6x-3 = 15

Consider the equation:

6x-3 = 15

Add 3 to both sides:

6x = 18

Divide both sides by 6:

x = \dfrac {18} {6}

x =3

The solution is x=3

-x-1 = -4

Let's solve the equation:

-x-1 = -4

Add 1 to both sides:

-x=-3

Divide both sides by -1:

x = \dfrac {-3} {- 1}

x =3

The solution is x=3.

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See also
  • Course : Linear equations
  • Exercise : Solve a linear equation with algebra tiles
  • Exercise : Solve a linear equation using graphs
  • Exercise : Solve a linear equation with variables on both sides
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