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  1. Home
  2. 12th grade
  3. Algebra I
  4. Exercise : Solve a linear equation with variables on both sides

Solve a linear equation with variables on both sides Algebra I

Solve the following linear equations.

-2x+3=-x-2

Consider the equation:

-2x+3=-x-2

Add 2x to both sides:

-2x+3+2x=-x-2+2x

3=x-2

Add 2 to both sides:

3+2=x-2+2

5=x

The solution is x=5.

2x-1=-x+5

Consider the equation:

2x-1=-x+5

Add x to both sides:

2x -1 + x = -x+5 + x

3x-1=5

Add 1 to both sides:

3x-1+1=5+1

3x=6

Divide both sides by 3.

\dfrac{3x}{3}=\dfrac{6}{3}

x=2

The solution is x=2.

-3x-3=x+-5

Consider the equation:

-3x-3 = x +5

Add 3x to both sides:

-3x-3 + 3x = x + 5 + 3x

-3 = 4x+5

Subtract 5 from both sides:

-3 -5 = 4x+5 - 5

-8=4x

Divide both sides by 4.

\dfrac{-8}{4}=\dfrac{4x}{4}

x=-2

The solution is x=-2

-x-3=3x+1

Consider the equation:

-x-3=3x+1

Add x to both sides:

-x-3+x = 3x + 1+x

-3 = 4x+1

Subtract 1 from both sides:

-3 -1= 4x + 1-1

-4 = 4x

Divide both sides by 4.

\dfrac{-4}{4}=\dfrac{4x}{4}

x=-1

The solution is x=-1

-x + 5 = -2x-3

Consider the equation:

-x + 5 = -2x-3

Add x to both sides:

-x + 5 +x= -2x-3+x

5=-x-3

Add 3 to both sides:

5+3 = -x-3+3

8=-x

Divide both sides by -1.

\dfrac {8} {-1} = \dfrac {-x} {-1}

x = -8

The solution is x=-8.

5x-2=-4x+7

Consider the equation:

5x-2=-4x+7

Add 4x to both sides:

5x-2 +4x= -4x+7+4x

9x-2=7

Add 2 to both sides:

9x-2+2 = 7+2

9x=9

Divide both sides by 9.

\dfrac {9x} {9} = \dfrac {9} {9}

x = 1

The solution is x=1.

9-2x=3x-11

Consider the equation:

9-2x=3x-11

Add 2x to both sides:

9-2x+2x = 3x-11+2x

9=5x-11

Add 11 to both sides:

9+11 = 5x-11+11

5x=20

Divide both sides by 5.

\dfrac {5x} {5} = \dfrac {20} {5}

x = 4

The solution is x=4.

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See also
  • Course : Linear equations
  • Exercise : Solve a linear equation with algebra tiles
  • Exercise : Solve a linear equation using simple operations
  • Exercise : Solve a linear equation using graphs
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