Divide complex numbers Algebra II

What is the algebric form of the following complex numbers?

\dfrac{3+4i}{2-i}

\dfrac{2+11i}{5}

\dfrac{2-11i}{5}

\dfrac{3+14i}{8}

\dfrac{9+12i}{11}

\dfrac{2+3i}{1-2i}

\dfrac{-1+9i}{2}

\dfrac{-1-4i}{2}

\dfrac{-3+8i}{2}

\dfrac{-4+7i}{5}

\dfrac{2-4i}{i}

-4+2i

4+2i

4-2i

-4-2i

\dfrac{1+2i}{1-i}

\dfrac{3-4i}{2}

\dfrac{-2+5i}{2}

\dfrac{-1+3i}{2}

\dfrac{1+2i}{2}

\dfrac{5+6i}{2-3i}

\dfrac{18+12i}{11}

\dfrac{-8+27i}{13}

\dfrac{8+17i}{11}

\dfrac{2+27i}{9}

\dfrac{7-2i}{5-2i}

\dfrac{9+4i}{11}

\dfrac{14+4i}{13}

\dfrac{39+4i}{29}

\dfrac{4+11i}{13}

\dfrac{1+i}{1-i}

1+i

i^2

1-i